WebbThe sum of first n terms of an A.P. is 3n2 +4n. Find the 25th term of this A.P. Solution Given S n = 3n 2 + 4n S 1 = 3×1 + 4×1 = 7. S 2 = 3×4 + 4×2 = 12 + 8 = 20. Therfore First term a 1 = 7 & Second term a 2 = 20 - 7 = 13 and d = 13 - 7 = 6. Now 25 th term a n = 7 + ( 25 - 1) 6 a 25 = 7 + 24 x 6 a 25 = 151. Suggest Corrections 12 Similar questions Webb30 mars 2024 · Ex 9.3, 23 If the first and the nth term of a G.P. are a and b, respectively, and if P is the product of n terms, prove that P2 = (ab)n. Let a be the first term of G.P & r be …
Formulas for AP and GP and HP AP and GP and HP PrepInsta
WebbFormula to find the nth term of an AP is T n = a + (n – 1) d where t n = nth term, a= first term , d= common difference, n = number of terms in the sequence. Number of terms in … Webb7 apr. 2024 · If the sum and product of first 3 terms of a decreasing AP are 54 and 5760 respectively, then the maximum possible value of sum of first n terms (n∈N) is (Sn)max= ? 220. 110. 5050. documenting workflows
Mean of the first n terms of the A.P. a, (a + d), (a + 2d), ........ is
WebbSum of n terms of AP = n/2[2a + (n – 1)d] For AP of natural numbers, a = 1 and d = 1, Sum of n terms S n of this AP can be found using the formula-Sn = n/2[2×1+(n-1)1] S n = … Webb15 okt. 2024 · The sum of n terms of an AP is 2n² + 5n. To find : The second term of the AP . Solution : Step 1 of 2 : Write down the given sum . Here it is given that the sum of n terms of an AP is 2n² + 5n . Sₙ = 2n² + 5n . Step 2 of 2 : Find second term of the AP . Putting n = 1 , 2 we get . S₁ = 2 × 1² + 5 × 1 = 2 + 5 = 7. ∴ First term = 7 Webb30 mars 2024 · Ex 5.4, 2 (Optional) The sum of the third and the seventh terms of an AP is 6 and their product is 8. Find the sum of first sixteen terms of the AP. We know that nth term of an AP is an = a + (n − 1)d Hence, 3rd term of … extreme mutha don\\u0027t wanna go to school today