WebINSERT newView SELECT NEWID (), A, B, C, D, E, F FROM MyTable and the trigger could be as simple as: CREATE trg_newview_insert TRIGGER newView INSTEAD OF UPDATE AS INSERT table1 SELECT ID, A, B, C FROM inserted INSERT table2 SELECT ID, D, E, F FROM inserted GO assuming the view is something like: WebSet the primary key using fields you already have in Access. Open the database that you want to modify. In the Navigation Pane, right click the table in which you want to set the primary key and, on the shortcut menu, click Design View. ... Select the field or fields that you want to use as the primary key .
Insert into table returning primary key (auto number) in resultset
WebJul 14, 2016 · I need to get the primary keys assigned in the trigger into my output table, but it always returns null. If I assign a DEFAULT value (pk UNIQUEIDENTIFIER … WebSep 19, 2024 · SQL Error: ORA-01752: cannot delete from view without exactly one key-preserved table 01752. 00000 – “cannot delete from view without exactly one key-preserved table” *Cause: The deleted table had – no key-preserved tables, – more than one key-preserved table, or – the key-preserved table was an unmerged view. brews on the beach 2022 clear lake ia
Get the new record key ID from MySQL insert query? - TutorialsPoint
WebJul 5, 2024 · The best (more efficient option) will depend on the expected probability of PK collision. If the chance of collision is high, then I'd save the DML overhead and do the SELECT first before the potential INSERT.. If the chance of collision is rare, then it is likely sufficient to do an INSERT IGNORE.. Note: if the PK is an auto_increment, a failed … WebCREATE PROCEDURE [CreateRecord] ( @value NVARCHAR (128), @id INT = NULL OUTPUT ) AS BEGIN INSERT [Records] ( [Value] ) VALUES ( @value ); SET @id = SCOPE_IDENTITY (); END Works for any type of key, including multi-column keys, but still only works when inserting a single record. WebAug 21, 2012 · --The below statement will retreive the primary key value where column NAME = @NAME and PINCODE = @Pincode and assign it to variable @Inserted_Identy SELECT @Inserted_Identy = Id from TableA Where NAME = @NAME and PINCODE = @Pincode END Update TableB Set TABLEA_ID = @Inserted_Identy Where ROOM_ID … county farm guilford county